PH = -Log10[H+]
POH = -Log10[OH-]
POH + PH = 14
[H+] x [OH] = 10-14
Was this helpful?Something wrong or missing? Tell us — we read every report and fix issues fast.
PH = -Log10[H+]
POH = -Log10[OH-]
POH + PH = 14
[H+] x [OH] = 10-14
Send feedback
Something wrong or missing? Tell us — we read every report and fix issues fast.